a~ij=(−1)i+j|a11⋯a1(j−1)a1(j+1)⋯a1n⋮⋮⋮a(i−1)1⋯⋯a(i−1)1a(i+1)1⋯⋯a(i+1)1⋮⋮⋮an1⋯an(j−1)an(j+1)⋯ann|
A~=adj(A)=[a~11a~21⋯a~n1a~12a~22⋯a~n2⋮⋮⋱⋮a~1na~2n⋯a~nn]
det(A)=a1ja~1j+a2ja~2j+⋯+anja~nj=∑i=1naija~ij
det(A)=ai1a~i1+ai2a~i2+⋯+aina~in=∑j=1naija~ij
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